trex232
7 posts
msg #70308
- Ignore trex232 |
1/2/2009 9:09:32 AM
I want to add a line to my filter where the 34ema is 20% higher than the 8ema.
is the following language correct?
"and where {EMA(34)-EMA(8)} is above 20 percent"
thanx trex
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chetron
2,817 posts
msg #70309
- Ignore chetron |
1/2/2009 9:10:20 AM
NO
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marine2
963 posts
msg #70350
- Ignore marine2 |
1/3/2009 12:43:28 AM
Lol, explain yourself Chet.
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chetron
2,817 posts
msg #70354
- Ignore chetron
modified |
1/3/2009 9:58:49 AM
the difference is 20 percent above what?
of course i know what, but you have to put it in the code.
hth
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chetron
2,817 posts
msg #70355
- Ignore chetron |
1/3/2009 10:26:33 AM
maybe...
i am not good at "one liners".
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heypa
283 posts
msg #70357
- Ignore heypa |
1/3/2009 1:02:03 PM
Here is a one liner.
Try ema(34) divided by ema(8) is greater than 1.2
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chetron
2,817 posts
msg #70366
- Ignore chetron
modified |
1/3/2009 8:22:24 PM
VERY NICE, HEYPA, BUT NOT QUITE RIGHT.
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arby347
87 posts
msg #70379
- Ignore arby347 |
1/4/2009 2:00:32 PM
ema(8) divided by ema(34) is greater than 1.2
is what you should have said heypa
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chetron
2,817 posts
msg #70380
- Ignore chetron |
1/4/2009 2:35:49 PM
actually arby347, your results give an ema(8) above the ema(34) and trex asked for the ema(34) above the ema(8)
fwiw
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arby347
87 posts
msg #70381
- Ignore arby347 |
1/4/2009 2:59:49 PM
Yor are right Chetron.O stand corrected
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